University of Guadalajara Assembly Language 32x Programming Code

Assemblylanguage

Modify this code into a program that receives two numbers and prints the minimum. The program then doubles the minimum and compares it to another number. It will then print the new minimum.

Ex:

Input1 = 2

Input2=3

Minimum=2

Newinput1=4

Newinput2=3

Newminimum=3

MY CODE:

%include “asm_io.inc”segment .data

message1 db “Enter a number: “,0message2 db “Enter another number: “, 0message3 db “The larger number is: “, 0

segment .bss

input1 resd 1 ; first number entered

segment .text global asm_mainasm_main: enter 0,0 ; setup routine pusha

mov eax, message1 ; print out first message call print_string call read_int ; input first number mov [input1], eax

mov eax, message2 ; print out second message call print_string call read_int ; input second number (in eax)

xor ebx, ebx ; ebx = 0 cmp eax, [input1] ; compare second and first number setg bl ; ebx = (input2 > input1) ? 1 : 0 neg ebx ; ebx = (input2 > input1) ? 0xFFFFFFFF : 0 mov ecx, ebx ; ecx = (input2 > input1) ? 0xFFFFFFFF : 0 and ecx, eax ; ecx = (input2 > input1) ? input2 : 0 not ebx ; ebx = (input2 > input1) ? 0 : 0xFFFFFFFF and ebx, [input1] ; ebx = (input2 > input1) ? 0 : input1 or ecx, ebx ; ecx = (input2 > input1) ? input2 : input1

mov eax, message3 ; print out result call print_string mov eax, ecx call print_int call print_nl

popa mov eax, 0 ; return back to C leave ret