STATISTICS 10 MCQ

CAN ANY OF YOU ANSWER THEM CORRECTLY , REPLY ASAP.

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2

>ONLINE

TEST

7

irst name:

2
7

ase Sales

7

32

10

C

deviate from the predicted values (or from the regression line) by ______ million cases

A

B

C

D

A

B

C

D

A

B

C

D

A

B

C

D

Statistics

6

F

Regression 1

5

A

B

C

D

A

B

C

D

A

B

C

D

A

B

C

D

A

B

C

D

Last name: F
Enter your LETTER answers HERE
1
3
4
5
6
8
9
1

0
Next 5 questions are based on the following data relating cases sold of the brand of soft drink to media expenditure.
Media Expenditure C
($millions) (millions) Use the following calculations in the relevant formulas to answer the questions
65 980
46 960 n =
32 700 x̅ =
28 345 y̅ = 520
25 360 ∑xy = 153,3

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10 ∑(y − y̅)² = 773,450
18 180 ∑x² = 9,198 ∑(y − ŷ)² = 105,248.57
115 ∑(x − x̅)² = 2,030 ∑(ŷ − y̅)² = 668,201.43
1) The estimated regression equation predicts that for each additional $1 million in media expenditure, the case sales would increase by ______ million.
A 9.6
B 12.8
14.6
D 18.1
2) The regression model shows that on average observed values of

Case Sales
145.1
135.2
126.5
118.3
3) The regression model indicates that ______% of variations in case sales is explained by media expenditure
95.7
92.6
86.4
82.4
4) To build a confidence interval for the slope coefficient b₁ the standard error of b₁, se(b₁) is
3.22
2.89
1.99
1.26
5) To perform a test of hypothesis that the population slope parameter is zero, the test statistic t is
6.52
5.63
4.68
3.89
Use the following Excel regression output to answer the next 5 questions. The output shows the result of running a regression relating costs to production volume. Fill in the highlighted cells first.
SUMMARY OUTPUT
Regression
Multiple R 0.9877
R Square
Adjusted R Square 0.9695
Standard Error
Observations
ANOVA
df SS MS Signif F
160.071587 2.25E-04
Residual 184775.04
Total 7579083.33
Coefficients Std Error t Stat P-value Lower 95% Upper 95%
Intercept 617.662 428.31 1.442 0.2227 -571.51 1806.84
X Variable 1 8.755 0.0002
6) The percentage of the variations in cost explained by production volume is:
97.6%
93.0%
90.3%
87.7%
7) The predicted total cost when production volume is 1,000 is,
8,581
8,827
9,373
9,670
8) Given that the sum of the squared deviations of production volume is 96,470.83, the standard error of the slope coefficient is
1.280
1.084
0.888
0.692
9) The lower end of the 95% confidence interval for the slope coefficient is
5.16
6.83
8.98
9.49
10) The value of the t Stat for the slope coefficient is
12.65
10.17
7.69
5.21

K

0

D 0 Next 5 questions are based on the following data relating cases sold of the brand of soft drink to media expenditure.
A 0
C 0 Media Expenditure Case Sales
A 0 ($millions) (millions)
B 0 65 980
A 0 46 960
C 0 32 700
D 0 28 345
B 0 25 360
A 0 18 180
10 115
Use the following calculations in the relevant formulas to answer the questions
n = 7 ∑(x − x̅)² = 2,030
x̅ = 32 ∑(y − y̅)² = 773,450
y̅ = 520 ∑(y − ŷ)² = 105,248.57
∑xy =

∑(ŷ − y̅)² = 668,201.43

∑x² = 9,198
1) The estimated regression equation predicts that for each additional $1 million in media expenditure, the case sales would increase by ______ million.
A 9.6
B 12.8
C 14.6
D 18.1

(∑xy − nx̅y̅)/(∑x² − nx̅²) =

2)

A 145.1
B 135.2
C 126.5
D 118.3

√MSE

SSE/(n − 2)

∑(y − ŷ)² =

MSE =

se(e) = 145.1
3) The regression model indicates that ______% of variations in case sales is explained by media expenditure
A 95.7
B 92.6
C 86.4
D 82.4

/SST

∑(ŷ − y̅)² =

668,201.43

∑(y − y̅)² =

R² =

4) To build a confidence interval for the slope coefficient b₁ the standard error of b₁, se(b₁) is
A 3.22
B 2.89
C 1.99
D 1.26

se(e)/√∑(x − x̅)² =

5) To perform a test of hypothesis that the population slope parameter is zero, the test statistic t is
A 6.52
B 5.63
C 4.68
D 3.89

b₁/se(b₁)

b₁ = 18.14
se(b₁) = 3.220
TS = 5.63
Use the following Excel regression output to answer the next 5 questions. The output shows the result of running a regression relating costs to production volume. Fill in the highlighted cells first.
SUMMARY OUTPUT
Multiple R 0.9877
R Square

Adjusted R Square 0.9695
Standard Error

Observations 6
ANOVA
df SS MS F Signif F
Regression 1

SSR 160.071587 2.25E-04

Residual 4 184775.04

Total 5 7579083.33
Coefficients Std Error t Stat P-value Lower 95% Upper 95%
Intercept 617.662 428.31 1.442 0.2227 -571.51 1806.84
X Variable 1 8.755

0.0002

6) The percentage of the variations in cost explained by production volume is:
A 97.6%
B 93.0%
C 90.3%
D 87.7%

R² = SSR/SST

SST = 7579083.33
SSE = 184775.04
SSR = 7394308.29
7) The predicted total cost when production volume is 1,000 is,
A 8,581
B 8,827
C 9,373
D 9,670

b₀ + b₁x

617.662

b₁ = 8.755
ŷ =

8) Given that the sum of the squared deviations of production volume is 96,470.83, the standard error of the slope coefficient is
A 1.280
B 1.084
C 0.888
D 0.692

se(e) = √MSE
MSE = SSE/(n − 2)
SSE = 184775.04

MSE = 46193.76
se(e) =

∑(x − x̅)² =

se(b₁) = 0.692
9) The lower end of the 95% confidence interval for the slope coefficient is
A 5.16
B 6.83
C 8.98
D 9.49

b₁ − MOE

tα/2,df se(b₁)

se(b₁) = 0.692

MOE =

b₁ =

L = 6.83
10) The value of the t Stat for the slope coefficient is
A 12.65
B 10.17
C 7.69
D 5.21

H₀: β₁ = 0 H₁: β₁ ≠ 0

b₁ = 8.76
se(b₁) = 0.692

TS = 12.65
NAME:
153,310
b₁ = 18.14
The regression model shows that on average observed values of Case Sales deviate from the predicted values (or from the regression line) by ______ million cases
se(e) =
MSE =
SSE = 105248.571428572
21049.7142857144
R² = SSR
SSR =
SST = 773,450.00
86.4%
se(b₁) = 3.220
H₀: β₁ = 0 H₁: β₁ ≠ 0
TS =
Regression Statistics
0.9756 R² = SSR/SST
214.93 se(e) = √MSE
7394308.29
46193.76 MSE = SSE/(n − 2)
0.6920 12.6520966579 6.834
SSR = SST − SSE
R² = SSR/SST = 97.56%
ŷ =
b₀ =
x = 1000
9373
se(b₁) = se(e)/√∑(x − x̅)²
214.9273365582
96470.83
L =
MOE =
tα/2,df = t0.025,4 = 2.776
1.92
8.76
TS = b₁/se(b₁)

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