I have 5 probability problems that I need to be added to a template
MAT540Homework
Week 3
Page 1 of 3
MAT540
Week 3 Homework
Chapter 14
1. The Hoylake Rescue Squad receives an emergency call every 1, 2, 3, 4, 5, or 6 hours, according to
the following probability distribution. The squad is on duty 24 hours per day, 7 days per week:
Time Between
Emergency Calls (hr.)
Probability
1 0.15
2 0.10
3 0.20
4
0.25
5 0.20
6 0.10
1.00
a. Simulate the emergency calls for 3 days (note that this will require a “running” , or cumulative,
hourly clock), using the random number table.
b. Compute the average time between calls and compare this value with the expected value of the
time between calls from the probability distribution. Why are the result different?
2. The time between arrivals of cars at the Petroco Services Station is defined by the following
probability distribution:
Time Between
Emergency Calls (hr.)
Probability
1
0.35
2 0.25
3 0.20
4 0.20
1.00
MAT540 Homework
Week 3
Page 2 of 3
a. Simulate the arrival of cars at the service station for 20 arrivals and compute the average time
between arrivals.
b. Simulate the arrival of cars at the service station for 1 hour, using a different stream of random
numbers from those used in (a) and compute the average time between arrivals.
c. Compare the results obtained in (a) and (b).
3. The Dynaco Manufacturing Company produces a product in a process consisting of operations of
five machines. The probability distribution of the number of machines that will break down in a
week follows:
Machine Breakdowns
Per Week
Probability
0 0.10
1 0.20
2 0.15
3 0.30
4 0.15
5 0.10
1.00
a. Simulate the machine breakdowns per week for 20 weeks.
b. Compute the average number of machines that will break down per week.
4. Simulate the following decision situation for 20 weeks, and recommend the best decision.
A concessions manager at the Tech versus A&M football game must decide whether to have the
vendors sell sun visors or umbrellas. There is a 30% chance of rain, a 15% chance of overcast skies,
and a 55% chance of sunshine, according to the weather forecast in college junction, where the
game is to be held. The manager estimates that the following profits will result from each decision,
given each set of weather conditions:
MAT540 Homework
Week 3
Page 3 of 3
Decision Weather Conditions
Rain
0.35
Overcast
0.25
Sunshine
0.40
Sun visors $-400 $-200 $1,500
Umbrellas 2,100 0 -800
5. Every time a machine breaks down at the Dynaco Manufacturing Company (Problem 3), either 1, 2,
or 3 hours are required to fix it, according to the following probability distribution:
Repair Time (hr.) Probability
1 0.20
2 0.50
3 0.30
1.00
Simulate the repair time for 20 weeks and then compute the average weekly repair time.
>P of (lower bound)
Time between calls Time between calls .1
1 1 2 2 3 4 6 Time =
Simulation 5
1 RN Time between calls RN Time between calls Cumulative clock 6 7 8 9 11 Simulation RN 2 3 10 11 or ?
Simulation RN 1 2 3 1 4 8 10 12 Simulation Breakdown Week RN RN P(x) Cumulative Breakdown 2 2 0 0.2 1 7 0 10 0
2
1
Hoylake Rescue Squad
Probability
Time between calls
Simulation
P(x)
Cumulative
simulation Number
RN
Cumulative clock
0
5
0.1
0.2
3
0.25
4
0.2 5 5
0.1
6
1
7
8
EV =
9
Average
10
11
12
13
14
15
16
17
18
19
20
P2
Petroco service
Probability Cumulative
Time between arrival (min)
0.3
Counts
0.25 2 1
0.2 3 2
0.2 4 3
1 4
5
a. Avg Arrival time
b. Avg. arrival time
Compare a. and b.
10
12
13
14
15
16
17
18
19
20P3
Dynaco Manufacturing
Probability breakdown per week
P(x) Cumulative
Breakdown
Week
Breakdowns
0.1 0 1
0.2 1 2
0.15
0.3 3 4
0.15 4 5
0.1 5 6
1 7
8
9
Simulated avg. breakdown
Average breakdowns =
12
13
14
15
16
17
18
19
20
P4
Sun Visor
Umbrella
P(x) Cumulative Sun Visor Week RN
SunVisor ($)
Umbrella ($)
0.35
-400
0.25
-200
0.4
1500
5 6
P(x) Cumulative Umbrella 7
0.35
2100
0.25 0 9
0.4
-800
1 11
13
14
15
16
17
18
19
20 Average
P5
Dynaco Manufacturing
Table from P3
Repair Time
P(x) Cumulative
Repair (hrs)
Breakdown #
Repair time/breakdown
Repair Time/week
0.2 1 1 0 0.1 0
0.5
0.3 3 3 0 0.15 2
1 4 0 0.3 3
5 0 0.15 4
6 0 0.1 5
Simulated avg. repair time
8 0
9 0
Theoretically calculated
11 0
12 0
13 0
14 0
15 0
16 0
17 0
18 0
19 0
20 0
Average repair time