Precalculus

32 problems problem #20 if you cant read it is e^ln(x^2+4)  #21 if you cant read it is -9+e^lnx9

1. -/1 points

What is the value of In e2? LarATRMRP6 4.4.003.

“? n;c;~cln=:l]f1Rhai-ili(;ldlfjJ

·————————————————————————————————————————· 2. -/1 points

Can you solve 3x = 27 using a One-to-One Property?
0 Yes

0 No

[r~ ·RiiliinO_ffchal ~

LarATRMRP6 4.4.004.

“————————————————————————————————————————· 3. -/2 points

Determne whether each x-value is a solution of the equation.

2 3 X + 1 = 128
(a) x = -2

0 Yes, this is a solution.

0 No, this is not a solution.

(b) X= 5

0 Yes, this is a solution.
0 No, this is not a solution.

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LarATRMRP6 4.4.008.

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I

J

;i points

Fill in the blank.

An -Select- v 1 solution does not satisfy the original equation.

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5. -/1 points

Do you solve log4 x = 2 by using a One-to-One Property or an Inverse Property?
0 Inverse Propert

y

0 One-to-One Property

rr=·”Ri~d”~t=u_Kc=t;.t •. Ui iilJ

6. -/3 points

Determine whether each x-value is a solution of the equation”\

4eX- 1 = 60
(a) x = 1 + In 15

0 Yes, this is a solution.
0 No, this is not a solution.

(b) X~ 3.708

0 Yes, this is a solution.
0 No, this is not a solution.

(c) x =In 16

0 Yes, this is a solution.
0 No, this is not a solution.

rr=·· MUd It . ]_tt . ··w;w. It … lj ~JcttaiiiiCHit li}

j

WNN.v.ebassign.llElt/\wbiStudent/~signment-Responses/last?dep=7445672

LarATRMRP6 4.4.002.

LarATRMRP6 4.4.006.

LarATRMRP6 4.4.010.

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129-4.4

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;3 points LarATRMRP6 4.4.012.

/ Determine whether each x-value is a solution of the equation.
/

log 2(; x) = 2
(a) X:::: 2.4800

0 Yes, this is a solution.
0 No, this is not a solution.

(b) X=..!!_
3

0 Yes, this is a solution.
0 No, this is not a solution.

(c) x = 2.2
0 Yes, this is a solution.

0 No, this is not a solution.

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129-4.4
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/~/3 points LarATRMRP6 4.4.014.
I

/ Detemine whether each x-value is a solution of the equation.

In (2 + x) = 8. 7

(a) x = e8 ·7 – 2

0 Yes, this is a solution.
0 No, this is not a solution.

(b) X~ 600091/100

0 Yes, this is a solution.
0 No, this is not a solution.

(c) x = 1/2
0 Yes, this is a solution.

0 No, this is not a solution.

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I 1~-4A
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-/2 points LarATRMRP6 4.4.016.Ml.

Approximate the point of intersection of the graphs off and g. Then solve the equation f(x) = g(x)
algebraically to verify your approximation.

f(x) = 125x
g(x) = 625

ex, v) = c I I , I I >

eoo

g
•300

y

400

200

0 ~——,—-1~5—-2 — “i:S 3
)(

L , ~ lf -~” –. ji_U wltch}L]IC…._• -~ ficl;rM;di11

10.-/2 points LarATRMRP6 4.4.018.

Use a graphing utility to graph f and g in the same viewing window.

f(x) = 3-x + 1 – 4
g(x) = 77

Approximate the point of intersection of the graphs off and g. (Round your answers to three decimal

places).

(x, y) = ( )

Solve the equation f(x) = g(x) algebraically.

x=l I

i(=~c~~:=·llliCi*-… ftll
~~L2-‘·., r”

WNN.v.ebassign.netlv.eb’Student/~signment-Responses/last?dep=7445672 5112

129-4.4
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,~-11 points
I

Solve the exponential equation.

5x = 3125

X= I I

He 1 lr-·FiltaCI D_Rciiit .MOUi.tt}f

12.-/1 points

Solve the exponential equation.

1
gx = 729

X= I I

lr Aud It ij_ltchit Allout •Ill

13.-/1 points

Solve the exponential equation.

(1/6)x = 1296

x= I I

r·~peu I tr–·Riiad-lt -:-BJfchaiAaiOUtiill

14.-/1 points

Solve the exponential equation.

(..±.)X = ..!.§_ 5 25
x= I I

H I p 11 . AudIt tUlCJ.t Allout ttlJ

WMN.It\00assign.netf\t.d:l/Student/Assignment-Responsesllast?clep=7445672

LarATRMRP6 4.4.024.

LarATRMRP6 4.4.026.

LarATRMRP6 4.4.028.

LarATRMRP6 4.4.030.

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;.-/1 points
I

J Solve the exponential equation. (Round your answer to three decimal places.)
ex= 54

X= I I

N ih_; t r~~~-] [J—~-··1 ru~—r …..,. r_~”‘*”•J~Ct.t~E

16.-/1 points

Solve the exponential equation.

3x- 1 = _1_
27

X ::: r-1 ——.~

(.’ » ·c·–c~~- c·crl [jQaiM;datjJ
~ . ‘ . ‘ ,._ ‘ . t. t .;

p

17.-/1 points

Solve the logarithmic equation.

In x = -17

x==

He P lr···rt;aci-ii -H fiCild-AI.o..tf~l!

18.-/1 points

Solve the logarithmic equation.

logx 64 = 3
x= I I

He I i) w-~R.ai!CJ_~ctiaf Al.ol.tJill

WNN.v.ebassign.netlv.eb’Studeni/Assignment-Responsesllast?dep=7445672

LarATRMRP6 4.4.032.

LarATRMRP6 4.4.036.

LarATRMRP6 4.4.040.

LarATRMRP6 4.4.042.

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129-4.4
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l-/1 points

Solve the logarithmic equation. (Round your answer to three decimal places.)

ln(6x + 3) = 4
X= I I

f-~–,—–cc–·a r~. -… -;-··-. –::·-c:–.:ti
,;:! / 1 · Reldu . _i.C!*.~•·rj

LarATRMRP6 4.4.046.

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20.-/1 points LarATRMRP6 4.4.050.

Sirl”plify the expression.

t.ln( !'” 1 \ :•

: ~ .. ,. ~ :- [-=ccr;;alt!lu~•o
” ; . dJ_ ;H – . – t ‘

21.-/1 points LarATRMRP6 4.4.052.

Sifllllify the expression.

~-I + ,_.lu r

1 ‘ 11. —AUdia– tljfchai-N.Outl•ll

22.-/1 points LarATRMRP6 4.4.056.MI.

Solve the exponential equation algebraically. Approximate the result to three decimal places. (If there is

no solution,

enter NO SOLUTION.)

64 x = 2000

x= I I

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129-4.4
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J.-/1 points LarATRMRP6 4.4.062.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing

utility to verify your answer.

1100e- 2x = 75
x=l I

II RMd It -Jl [@f;t AbOut i!] I

24.-/1 points LarATRMRP6 4.4.066.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing
utility to verify your answer.

12(2 – l-x) + 11 == 2501

X= I I

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25.-/1 points LarATRMRP6 4.4.070.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing
utility to verify your answer.

(1 + 0.04)X == 250,000 30Q…:._ __ _
0.04

X== I I

H i 0 ; IQ;—:d1•:lf&tiit AliOut lti:l

26.-/1 points LarATRMRP6 4.4.078.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing
utility to verify your answer.

47″5 = 325

x= I I

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129-4.4
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/1.-11 points
I

LarATRMRP6 4.4.090.

Use a graphing utility to graph the function and approximate its zero accurate to three decimal places.

h(t) = e0.140t _ 6
t =I I

.d t:p If RNcln ]_[~~]

28.-/1 points LarATRMRP6 4.4.098.

Solve the logarithmic equation algebraically. Round the result to three decimal places. Verify your

answer using a graphing utility. (Enter your answers as a conTT’la-separated list. If there is no solution,

enter NO SOLUTION.)

3 + 41n x = 12

x=

el H _· -…. dlt – tj_KCh.t*.~t•1l

·————————————————————————————————————————·
29.-/1 points LarATRMRP6 4.4.110.MI.

Solve the logarithmc equation algebraically. Approximate the result to three decimal places. (If there is

no solution, enter NO SOLUTION.)

ln(x + 3) – ln{x – 3) = ln{x)
..–, —-.,

~, p’) [. RUCi·,.·]j f[·Mits.-rit···fj f!C:~.AbO.Itllfl

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129-4.
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. -/8 points LarATRMRP6 4.4.118 .

Consider the following.

, ..

5 log10(x- 6) = 11

(a) Coll’l>lete the table to find an interval containing the solution of the equation. Round your

results to three decimal places.

I
X

II
150

I II
155

I II
160

I II
165

I II
170

5 loglo(x- 6)

What is the smallest open interval based on the table above that contains the solution of the

equation? (Use the x-values given by the table.)

(b) Use a graphing utility to graph both sides of the equation to estimate the solution. Round
your result to three decimal places.

}f = I I

Cc) Solve the eauation algebraically. Round your result to three decimal places.
X= I I

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·————————————————————————————————————————· 31.-/1 points

LarATRMRP6 4.4.130.

Use a graphing utility to approximate the point of intersection of the graphs. Round your result to three
decimal places.

Y1 = 1.07

I ,-Y2 = n y X- 7

(x, y) = ( )

L~iiJJ_~~till

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129-4.4

/ ,-/1 points LarATRMRP6 4.4.136.

So\ve the equation algebraically. Round the result to three decimal places. Verify your answer using a

graphing utility.

3 -In X = O
x2

x=

lr -,_cfitJ !Jct.t Atlout itll

_.,;.

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