Math 3

 

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   Question 20

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Qu
esti
on

1

5 points
Sa
ve

Find the indicated intercept(s) of the graph of the function.

x-intercepts of

f(x) =

(9, 0)
(-9, 0)
(0, 0) and (-9, 0)
(0, 0) and (9, 0)

Qu
esti
on
2

5 points
Sa
ve

Find all zeros of the function and write the polynomial as a
product of linear factors.

f(x) = x4 + 6×3 + 17×2 + 54x + 72

f(x) = (x – 4)(x + 2)(x – 3)(x + 3)
f(x) = (x + 4)(x + 2)(x – 3i)(x + 3i)
f(x) = (x – 1)(x – 8)(x – 3i)(x + 3i)

f(x) = (x – i )(x + i )(x – 3)(x +3)

Qu
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on
3

5 points
Sa
ve

State whether the function is a polynomial function or not. If it is,
give its degree. If it is not, tell why not.

4(x – 1)12(x + 1)9

Yes; degree 48
Yes; degree 21
Yes; degree 4
Yes; degree 12

javascript:saveItem(‘_10020909_1′,’1’)

javascript:saveItem(‘_10020909_1′,’1’)

javascript:saveItem(‘_10020910_1′,’2’)

javascript:saveItem(‘_10020910_1′,’2’)

javascript:saveItem(‘_10020911_1′,’3’)

javascript:saveItem(‘_10020911_1′,’3’)

Qu
esti
on
3
5 points
Sa
ve

State whether the function is a polynomial function or not. If it is,
give its degree. If it is not, tell why not.
4(x – 1)12(x + 1)9

Yes; degree 48
Yes; degree 21
Yes; degree 4
Yes; degree 12

Qu
esti
on
4

5 points
Sa
ve

Find the x- and y-intercepts of f.

f(x) = (x + 2)(x – 3)(x + 3)

x-intercepts: -3, 3, 2; y-intercept: 18
x-intercepts: -2, -3, 3; y-intercept: 18
x-intercepts: -3, 3, 2; y-intercept: -18

x-intercepts: -2, -3, 3; y-intercept: -18�� Question 5�5 points �Save � �Give the equation of the ob

lique asymptote, if any, of the function.

f(x) =

y = x – 3
x = y – 3
y = x – 9

no oblique asymptotes

javascript:saveItem(‘_10020911_1′,’3’)

javascript:saveItem(‘_10020911_1′,’3’)

javascript:saveItem(‘_10020912_1′,’4’)

javascript:saveItem(‘_10020912_1′,’4’)

javascript:saveItem(‘_10020913_1′,’5’)

Qu
esti
on
6

5 points
Sa
ve

Find the indicated intercept(s) of the graph of the function.

y-intercept of f(x) =

(0, 3)
(0, 4)

Qu
esti
on
7

5 points
Sa
ve

Determine where the function is increasing and where it is
decreasing.

f(x) = -x2 – 4x + 5

increasing on (-∞, 9)
decreasing on (9, ∞)
increasing on (-2, ∞)
decreasing on (-∞, -2)
increasing on (-∞, -2)
decreasing on (-2, ∞)
increasing on (9, ∞)
decreasing on (-∞, 9)

javascript:saveItem(‘_10020914_1′,’6’)

javascript:saveItem(‘_10020914_1′,’6’)

javascript:saveItem(‘_10020915_1′,’7’)

javascript:saveItem(‘_10020915_1′,’7’)

Qu
esti
on
8

5 points
Sa
ve

Use the graph to find the horizontal asymptote, if any, of the
function.

y = 0
x = 2
y = 3
y = 0, y = 3

Qu
esti
on
9

5 points
Sa
ve

For the polynomial, list each real zero and its multiplicity.
Determine whether the graph crosses or touches the x-axis at each
x -intercept.

f(x) = 4(x – 1)3

– , multiplicity 4, touches x-axis; 1, multiplicity 3, crosses x-axis

, multiplicity 4, touches x-axis; -1, multiplicity 3, crosses x-axis

, multiplicity 4, crosses x-axis; -1, multiplicity 3, touches x-axis

– , multiplicity 4, crosses x-axis; 1, multiplicity 3, touches x-axis

javascript:saveItem(‘_10020916_1′,’8’)

javascript:saveItem(‘_10020916_1′,’8’)

javascript:saveItem(‘_10020917_1′,’9’)

javascript:saveItem(‘_10020917_1′,’9’)

Qu
esti
on
9
5 points
Sa
ve

For the polynomial, list each real zero and its multiplicity.
Determine whether the graph crosses or touches the x-axis at each
x -intercept.
f(x) = 4(x – 1)3
– , multiplicity 4, touches x-axis; 1, multiplicity 3, crosses x-axis
, multiplicity 4, touches x-axis; -1, multiplicity 3, crosses x-axis
, multiplicity 4, crosses x-axis; -1, multiplicity 3, touches x-axis

– , multiplicity 4, crosses x-axis; 1, multiplicity 3, touches x-axis

Qu
esti
on
10

5 points
Sa
ve

Use the x-intercepts to find the intervals on which the graph of f is
above and below the x-axis.

f(x) = (x – 2)2(x + 4)2

above the x-axis: (-4, 2)
below the x-axis: (-∞, -4), (2, ∞)
above the x-axis: no intervals
below the x-axis: (-∞, -4), (-4, 2), (2, ∞)
above the x-axis: (-∞, -4), (2, ∞)
below the x-axis: (-4, 2)
above the x-axis: (-∞, -4), (-4, 2), (2, ∞)
below the x-axis: no intervals

Qu
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on
11

5 points
Sa
ve

Solve.

While traveling in a car, the centrifugal force a passenger experiences
as the car drives in a circle varies jointly as the mass of the passenger
and the square of the speed of the car. If the a passenger experiences
a force of 162 newtons when the car is moving at a speed of 60
kilometers per hour and the passenger has a mass of 50 kilograms,
find the force a passenger experiences when the car is moving at 40
kilometers per hour and the passenger has a mass of 100 kilograms.

128 newtons
144 newtons
160 newtons
176 newtons

javascript:saveItem(‘_10020917_1′,’9’)

javascript:saveItem(‘_10020917_1′,’9’)

javascript:saveItem(‘_10020918_1′,’10’)

javascript:saveItem(‘_10020918_1′,’10’)

javascript:saveItem(‘_10020919_1′,’11’)

javascript:saveItem(‘_10020919_1′,’11’)

Qu
esti
on
11
5 points
Sa
ve

Solve.
While traveling in a car, the centrifugal force a passenger experiences
as the car drives in a circle varies jointly as the mass of the passenger
and the square of the speed of the car. If the a passenger experiences
a force of 162 newtons when the car is moving at a speed of 60
kilometers per hour and the passenger has a mass of 50 kilograms,
find the force a passenger experiences when the car is moving at 40
kilometers per hour and the passenger has a mass of 100 kilograms.

128 newtons
144 newtons
160 newtons
176 newtons

Qu
esti
on
12

5 points
Sa
ve

Use the graph to find the vertical asymptotes, if any, of the
function.

x = -3, x = 3, x = 0
x = -3, x = 3, y = 0
none
x = -3, x = 3

javascript:saveItem(‘_10020919_1′,’11’)

javascript:saveItem(‘_10020919_1′,’11’)

javascript:saveItem(‘_10020920_1′,’12’)

javascript:saveItem(‘_10020920_1′,’12’)

Qu
esti
on
12
5 points
Sa
ve

Use the graph to find the vertical asymptotes, if any, of the
function.

x = -3, x = 3, x = 0
x = -3, x = 3, y = 0
none
x = -3, x = 3

Qu
esti
on
13

5 points
Sa
ve

Solve the equation in the real number system.

2×4 – 2×3 + x2 – 5x – 10 = 0

�{-1, 2}�������{1, -2}�����

javascript:saveItem(‘_10020920_1′,’12’)

javascript:saveItem(‘_10020920_1′,’12’)

javascript:saveItem(‘_10020921_1′,’13’)

javascript:saveItem(‘_10020921_1′,’13’)

Qu
esti
on
15

5 points
Sa
ve

Find the vertex and axis of symmetry of the graph of the function.

f(x) = -5×2 – 2x – 2

; x = -5

; x =
(5, -2); x = 5

; x = –

Qu
esti
on
16

5 points
Sa
ve

Solve.

The power that a resistor must dissipate is jointly proportional to the
square of the current flowing through the resistor and the resistance of
the resistor. If a resistor needs to dissipate of power when

of current is flowing through the resistor whose resistance
is find the power that a resistor needs to dissipate when

of current are flowing through a resistor whose resistance is

63 watts
147 watts
84 watts
21 watts

Qu
esti
on
17

5 points
Sa
ve

Find all zeros of the function and write the polynomial as a
product of linear factors.

f(x) = x3 + 8×2 + 22x + 20

f(x) = (x + 2)(x + 3 + i)(x + 3 – i)
f(x) = (x + 2)(x + 3 + i)(x – 3 – i)

f(x) = (x – 1)(x + 3 + i )(x + 3 – i )

f(x) = (x + 1)(x + 3 + i )(x – 2 – i )

javascript:saveItem(‘_10020923_1′,’15’)

javascript:saveItem(‘_10020923_1′,’15’)

javascript:saveItem(‘_10020924_1′,’16’)

javascript:saveItem(‘_10020924_1′,’16’)

javascript:saveItem(‘_10020925_1′,’17’)

javascript:saveItem(‘_10020925_1′,’17’)

Qu
esti
on
17
5 points
Sa
ve

Find all zeros of the function and write the polynomial as a
product of linear factors.
f(x) = x3 + 8×2 + 22x + 20
f(x) = (x + 2)(x + 3 + i)(x + 3 – i)
f(x) = (x + 2)(x + 3 + i)(x – 3 – i)
f(x) = (x – 1)(x + 3 + i )(x + 3 – i )

f(x) = (x + 1)(x + 3 + i )(x – 2 – i )

Qu
esti
on
18

5 points
Sa
ve

Solve the inequality.

(x + 1)(x – 3) ≤ 0

(-∞, -1]
[-1, 3]
[3, ∞)
(-∞, -1] or [3, ∞)

Qu
esti
on
19

5 points
Sa
ve

Solve the inequality.

≥ 0

(-∞, -7) or [-2, 6) or [12, ∞)
(-∞, -7) or [12, ∞)
(-7, -2] or (6, 12]
(-∞, -7) or [-2, 0) or (0, 6) or [12, ∞)

javascript:saveItem(‘_10020925_1′,’17’)

javascript:saveItem(‘_10020925_1′,’17’)

javascript:saveItem(‘_10020926_1′,’18’)

javascript:saveItem(‘_10020926_1′,’18’)

javascript:saveItem(‘_10020927_1′,’19’)

javascript:saveItem(‘_10020927_1′,’19’)

Qu
esti
on
19
5 points
Sa
ve

Solve the inequality.
≥ 0

(-∞, -7) or [-2, 6) or [12, ∞)
(-∞, -7) or [12, ∞)
(-7, -2] or (6, 12]
(-∞, -7) or [-2, 0) or (0, 6) or [12, ∞)

Qu
esti
on
20

5 points
Sa
ve

Form a polynomial whose zeros and degree are given.

Zeros: -1, 1, – 2; degree 3

f(x) = x3 – 2×2 + x – 2 for a = 1

f(x) = x3 – 2×2 – x + 2 for a = 1

f(x) = x3 + 2×2 + x + 2 for a = 1

f(x) = x3 + 2×2 – x – 2 for a = 1

javascript:saveItem(‘_10020927_1′,’19’)

javascript:saveItem(‘_10020927_1′,’19’)

javascript:saveItem(‘_10020928_1′,’20’)

javascript:saveItem(‘_10020928_1′,’20’)

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math 3.rtfd/TXT.rtf
 Question 1

5 points  

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Find the indicated intercept(s) of the graph of the function.
x-intercepts of f(x) = f1q42g1 ¬

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(9, 0)(-9, 0)(0, 0) and (-9, 0)(0, 0) and (9, 0)

1__#$!@%!#__spacer.gif ¬   Question 2

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Find all zeros of the function and write the polynomial as a product of linear factors.
f(x) = x4 + 6×3 + 17×2 + 54x + 72

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f(x) = (x – 4)(x + 2)(x – 3)(x + 3)f(x) = (x + 4)(x + 2)(x – 3i)(x + 3i)f(x) = (x – 1)(x – 8)(x – 3i)(x + 3i)f(x) = (x – if1q77g1 ¬)(x + if1q77g2 ¬)(x – 3)(x +3)

3__#$!@%!#__spacer.gif ¬   Question 3

5 points  

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State whether the function is a polynomial function or not. If it is, give its degree. If it is not, tell why not.
4(x – 1)12(x + 1)9

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Yes; degree 48Yes; degree 21Yes; degree 4Yes; degree 12

5__#$!@%!#__spacer.gif ¬   Question 4

5 points  

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Find the x- and y-intercepts of f.
f(x) = (x + 2)(x – 3)(x + 3)

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x-intercepts: -3, 3, 2; y-intercept: 18x-intercepts: -2, -3, 3; y-intercept: 18x-intercepts: -3, 3, 2; y-intercept: -18x-intercepts: -2, -3, 3; y-intercept: -18

7__#$!@%!#__spacer.gif ¬   Question 5

5 points  

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Give the equation of the oblique asymptote, if any, of the function.
f(x) = f1q49g1 ¬

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y = x – 3x = y – 3y = x – 9no oblique asymptotes

9__#$!@%!#__spacer.gif ¬   Question 6

5 points  

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Find the indicated intercept(s) of the graph of the function.
y-intercept of f(x) = f1q1g1 ¬

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(0, 3)(0, 4)f1q1g2 ¬f1q1g3 ¬

11__#$!@%!#__spacer.gif ¬   Question 7

5 points  

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Determine where the function is increasing and where it is decreasing.
f(x) = -x2 – 4x + 5

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increasing on (-∞, 9)
decreasing on (9, ∞)increasing on (-2, ∞)
decreasing on (-∞, -2)increasing on (-∞, -2)
decreasing on (-2, ∞)increasing on (9, ∞)
decreasing on (-∞, 9)

13__#$!@%!#__spacer.gif ¬   Question 8

5 points  

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Use the graph to find the horizontal asymptote, if any, of the function.

f1q108g1 ¬

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y = 0x = 2y = 3y = 0, y = 3

15__#$!@%!#__spacer.gif ¬   Question 9

5 points  

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For the polynomial, list each real zero and its multiplicity. Determine whether the graph crosses or touches the x-axis at each x -intercept.
f(x) = f1q53g1 ¬4(x – 1)3

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– f1q53g2 ¬, multiplicity 4, touches x-axis; 1, multiplicity 3, crosses x-axisf1q53g3 ¬, multiplicity 4, touches x-axis; -1, multiplicity 3, crosses x-axisf1q53g4 ¬, multiplicity 4, crosses x-axis; -1, multiplicity 3, touches x-axis- f1q53g5 ¬, multiplicity 4, crosses x-axis; 1, multiplicity 3, touches x-axis

17__#$!@%!#__spacer.gif ¬   Question 10

5 points  

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Use the x-intercepts to find the intervals on which the graph of f is above and below the x-axis.
f(x) = (x – 2)2(x + 4)2

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above the x-axis: (-4, 2)
below the x-axis: (-∞, -4), (2, ∞)above the x-axis: no intervals
below the x-axis: (-∞, -4), (-4, 2), (2, ∞)above the x-axis: (-∞, -4), (2, ∞)
below the x-axis: (-4, 2)above the x-axis: (-∞, -4), (-4, 2), (2, ∞)
below the x-axis: no intervals

19__#$!@%!#__spacer.gif ¬   Question 11

5 points  

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Solve.
While traveling in a car, the centrifugal force a passenger experiences as the car drives in a circle varies jointly as the mass of the passenger and the square of the speed of the car. If the a passenger experiences a force of 162 newtons when the car is moving at a speed of 60 kilometers per hour and the passenger has a mass of 50 kilograms, find the force a passenger experiences when the car is moving at 40 kilometers per hour and the passenger has a mass of 100 kilograms.

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128 newtons144 newtons160 newtons176 newtons

21__#$!@%!#__spacer.gif ¬   Question 12

5 points  

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Use the graph to find the vertical asymptotes, if any, of the function.

f1q5g1 ¬

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x = -3, x = 3, x = 0x = -3, x = 3, y = 0nonex = -3, x = 3

23__#$!@%!#__spacer.gif ¬   Question 13

5 points  

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Solve the equation in the real number system.
2×4 – 2×3 + x2 – 5x – 10 = 0

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{-1, 2}f1q54g1 ¬{1, -2}f1q54g2 ¬

25__#$!@%!#__spacer.gif ¬   Question 14

5 points  

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Give the equation of the horizontal asymptote, if any, of the function.
f(x) = f1q116g1 ¬

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y = 2y = 6y = 1no horizontal asymptotes

27__#$!@%!#__spacer.gif ¬   Question 15

5 points  

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Find the vertex and axis of symmetry of the graph of the function.
f(x) = -5×2 – 2x – 2

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f1q22g1 ¬; x = -5f1q22g2 ¬; x = f1q22g3 ¬(5, -2); x = 5f1q22g4 ¬; x = – f1q22g5 ¬

29__#$!@%!#__spacer.gif ¬   Question 16

5 points  

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Solve.
The power that a resistor must dissipate is jointly proportional to the square of the current flowing through the resistor and the resistance of the resistor. If a resistor needs to dissipate f1q26g1 ¬ of power when f1q26g2 ¬ of current is flowing through the resistor whose resistance is f1q26g3 ¬ find the power that a resistor needs to dissipate when f1q26g4 ¬ of current are flowing through a resistor whose resistance is f1q26g5 ¬

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63 watts147 watts84 watts21 watts

31__#$!@%!#__spacer.gif ¬   Question 17

5 points  

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Find all zeros of the function and write the polynomial as a product of linear factors.
f(x) = x3 + 8×2 + 22x + 20

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f(x) = (x + 2)(x + 3 + i)(x + 3 – i)f(x) = (x + 2)(x + 3 + i)(x – 3 – i)f(x) = (x – 1)(x + 3 + if1q10g1 ¬)(x + 3 – if1q10g2 ¬)f(x) = (x + 1)(x + 3 + if1q10g3 ¬)(x – 2 – if1q10g4 ¬)

33__#$!@%!#__spacer.gif ¬   Question 18

5 points  

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Solve the inequality.
(x + 1)(x – 3) ≤ 0

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(-∞, -1][-1, 3][3, ∞)(-∞, -1] or [3, ∞)

35__#$!@%!#__spacer.gif ¬   Question 19

5 points  

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Solve the inequality.
f1q32g1 ³ 0

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(-∞, -7) or [-2, 6) or [12, ∞)(-∞, -7) or [12, ∞)(-7, -2] or (6, 12](-∞, -7) or [-2, 0) or (0, 6) or [12, ∞)

37__#$!@%!#__spacer.gif ¬   Question 20

5 points  

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Form a polynomial whose zeros and degree are given.
Zeros: -1, 1, – 2; degree 3

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f(x) = x3 – 2×2 + x – 2 for a = 1f(x) = x3 – 2×2 – x + 2 for a = 1f(x) = x3 + 2×2 + x + 2 for a = 1f(x) = x3 + 2×2 – x – 2 for a = 1

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