laplac

please see attached.

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  • General Information
  • All questions in the tasks must be completed correctly with sufficient detail to gain the
    pass criteria.

    All submissions to be electronic in MS Word format with a minimum of 20 typed
    words. Also add footer to the document with your name. All answers must be clearly
    identified as to which task and question they refer to. All work must be submitted
    through Learnzone.

  • Task 1 – Learning Outcome 2.1
  • Determine Laplace transforms and their inverse using tables and partial
    fractions

    1. Find the Laplace transform of each of the following

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    a. 8 + 3𝑑𝑑 βˆ’ 2𝑑𝑑
    2

    3
    βˆ’ 2𝑑𝑑6 + 𝑒𝑒3𝑑𝑑 + 𝑠𝑠𝑠𝑠𝑠𝑠3𝑑𝑑 βˆ’ π‘π‘π‘π‘π‘ π‘ β„Ž2𝑑𝑑

    b. οΏ½
    3 𝑐𝑐𝑐𝑐𝑠𝑠2𝑑𝑑+2 𝑒𝑒3𝑑𝑑 +2 𝑑𝑑4 + 3𝑑𝑑+4

    𝑒𝑒5𝑑𝑑
    οΏ½

    2. Find the inverse Laplace transforms of the following functions

    a.

    3
    π‘ π‘ βˆ’2

    +
    2
    𝑠𝑠+1

    +
    3

    (𝑠𝑠+1)5

    b.
    2
    𝑠𝑠

    +
    4
    𝑠𝑠5

    +
    𝑠𝑠

    𝑠𝑠2 +16

    c. 𝑠𝑠+4
    𝑠𝑠2 +4𝑠𝑠+4

    d. 4
    (π‘ π‘ βˆ’1)(𝑠𝑠+2)

  • Task 2 – Learning Outcome 2.2
  • Solve first and second order differential equations using Laplace transforms

    3. Solve the following first order differential equations using Laplace transforms

    𝑑𝑑𝑠𝑠
    𝑑𝑑𝑑𝑑

    + 3𝑠𝑠 = 2π‘’π‘’βˆ’5𝑑𝑑 𝑠𝑠(0) = 3

    4. Use Laplace transform to solve the following second order differential equation

    𝑣𝑣′′ + 2𝑣𝑣′ + 𝑣𝑣 = 𝑑𝑑2 βˆ’ 1 𝑣𝑣(0) = 1, 𝑣𝑣′ (0) = βˆ’1

  • Task 3 – Learning Outcome 2.3
  • Model and analyse engineering systems and determine system behaviour
    using Laplace transforms

    5. A series LR circuit with a step input voltage can be modelled by the equation:

    𝐿𝐿

    𝑅𝑅
    𝑑𝑑𝑠𝑠
    𝑑𝑑𝑑𝑑

    + 𝑠𝑠 = 𝑉𝑉
    𝑅𝑅
    , i(0)=0 L, R and V are constants

    Use Laplace transforms to show:

    𝑠𝑠 = 𝑉𝑉
    𝑅𝑅
    οΏ½1 βˆ’ π‘’π‘’βˆ’

    𝑅𝑅
    𝐿𝐿
    𝑑𝑑�

    6. The charge in a series LCR circuit is modeled by the equation:

    𝐿𝐿 𝑑𝑑
    2π‘žπ‘ž
    𝑑𝑑𝑑𝑑2

    + 𝑅𝑅 π‘‘π‘‘π‘žπ‘ž
    𝑑𝑑𝑑𝑑

    + π‘žπ‘ž
    𝐢𝐢

    = 𝑠𝑠𝑠𝑠𝑠𝑠𝑑𝑑 π‘žπ‘ž(0) = 0, π‘žπ‘žβ€²(0) = 0

    Solve the equation in case when L=2 H, R=20 Ω, C=0.02 F

    End of assessment brief

      General Information
      Task 1 – Learning Outcome 2.1
      Task 2 – Learning Outcome 2.2
      ,𝑑𝑖-𝑑𝑑.+3𝑖=2,𝑒-βˆ’5𝑑. 𝑖,0.=3
      Task 3 – Learning Outcome 2.3

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