This is for https://courseworkhero.co.uk/ (2nd)

Hi Morga

 

Please see the attachments ..

qlt_task5_0612 x
A. Joe, a newly hired employee of a News Agency, needs a new cell phone for his job. His company gives him an allowance of $300.00 for his communication line. It is up to him to consume this allowance or save some of it as long as his communication with his company will never be affected.
Now, he meets up with a sales agent of a network service provider who has offered Joe two options: Plan 250 and Plan 300. Plan 250 will require Joe to pay $250 monthly which offers 20 Hours Voice Messaging and unlimited free Text Messages consumable. While the Plan 300, will require Joe to pay $275 monthly with unlimited call and text. Plan 250 charges the rate of voice messaging @ $10/hour when the consumables are used up. Joe was offered these two options since he is expected to use 20 or up to 30 hours of voice messaging. Investigate what Plan should Joe choose and show him his options and limits.

B.
Let y be the amount to be paid monthly and x be the hours used in making voice calls.
Plan 250: y
This is because at x 20 the charge is fixed at $250 otherwise the rate of $10 is added per hour.

Plan 300: y=300

Equating the two equations:

250 + 10(x-20) = 300
(
Point where the two Plans will be equal (25, 300), after this point it will be better for Joe to choose Plan 300
)250 + 10x – 200 = 300, distributing 10 to (x-20)
10x = 300 + 200 – 250, transposing all constants to the right side
10x = 250, simplifying
x = 25, dividing both sides by 10 @ x = 25, Plan 250 will pay $300
therefore the solution set is at (25, 300)

_
PLAN 250 10 Hours 20 Hours 30 Hours 250 250 350 PLAN 300 10 Hours 20 Hours 30 Hours 300 300 300 Column1 10 Hours 20 Hours 30 Hours

revised_rqlt_task_2_V1 x
1.
y = -(2/3)x + 30
this form follows the slope-intercept form:
y = mx + b, where b is the y-intercept.
b = 30, therefore y – intercept is 30
(0, 30)
to find the x – intercept set y = 0
0 = -(2/3)x + 30, transpose term with x to left side
(2/3)x = 30, multiply 3/2 both sides
(
y-intercept
(0, 30)
this
also represent the 3
rd
story window (0, 30)
)x = 45, x – intercept is at (45, 0)

(
x-intercept
(45, 0)
this
also represent the point on the ground where the beam hit (45, 0)
)@ x = -30 we solve for y:
y = – (2/3)(30) + 30
y = -20 + 30
y = 10 (height of the beam @ 30 ft
away from the building as
shown also in the graph)

(
Note: every division line in the y – axis is incremented by 10 units, and 5 units for every line division on x – axis.
)

The first quadrant of the graph is the relevant part for
this problem. This graph maybe a good representation of
the problem since a third-story window maybe realistically
represented by a height of 30-feet and the beam following
a line path y=-(2/3)x + 30, will hit the ground 45 feet away from the building.

revised_rqlt_task_3_v1 x
Plan A:
y = 20x + 400

Plan B:
y = 10x + 600

solving for amount when Plan A = Plan B we equate equation 1 and 2
20x + 400 = 10x + 600, transpose all terms with x on the left
20x – 10x = 600 – 400, simplifying
10x = 200
x = 20

@ x = 20 we get:
Plan A: y = 20(20) + 400 = $800 or
(
Solution (20, 800)
)Plan B: y = 10(20) + 600 = $800
(
Solution (20, 800)
)Both Plans will have an equal amount of $800 after 20 months (x = 20 months)
(
@ 14 months Plan B has a higher amount of savings.
)
(
y –
axis
(amount of money in $100)
)

(
900
) (
800
)
(
Solution (20, 800)
)
(
@ 14 months Plan B has a higher amount of savings.
) (
700
) (
600
) (
y –
intercept
(0, 600)
)
(
500
)
(
x = 14 months
) (
400
) (
y –
intercept
(0, 400)
)
(
x = 23 months
) (
Solution (20, 800)
) (
300
)
(
200
)
(
100
)
(
x –
axis
(number of months)
)
(
2
0
) (
15
) (
5
) (
1
) (
10
)

Legend:
Plan A
Plan B The first quadrant is the relevant quadrant on this.

RQLT Task 2 rev 2
Graph of the Equation – The candidate accurately graphs the equation, with limited detail.
**Criterion Score: 1.00
Comments on this criterion: The graph has improved. The necessary descriptive labeling for each axis could not be located. Please revise the graph as needed.

RQLT Task 3 rev 2
A3a2. Savings After 23 Months – The candidate does not accurately determine which plan yields the greatest balance if the person stops saving after 23 months
**Criterion Score: 0.00
Comments on this criterion: Plan B is incorrect.
A4. Relevant Quadrants – The candidate provides a logical explanation, with insufficient detail, of which quadrant(s) of the graph is(are) relevant.
**Criterion Score: 1.00
Comments on this criterion: Quadrant 1 is correct. The current response lacks sufficient detail to meet the requirements for this question.

QLT Task 5 rev 1
C. Graphical Representation of Cost Options – The candidate provides an accurate graphic depiction of the real-world problem, with no detail, using appropriate graphing software.
**Criterion Score: 1.00
Comments on this criterion: The graph is correct but a descriptive label is required for the y-axis.

D. Decision-Making Process – The candidate provides a logical discussion, with no support, of a decision-making process that is based on both mathematical reasoning and non-financial, or situational, considerations.
**Criterion Score: 1.00
Comments on this criterion: No decision-making process was described other than the statement that the “point where the two Plans will be equal (25, 300), after this point it will be better for Joe to choose Plan 300” but other factors may be necessary when determining the final customer recommendation.

D1. Final Recommendation – The candidate does not provide a logical discussion of the final recommendation that states the option that most closely meets the consumer’s financial needs and non-financial considerations.
**Criterion Score: 0.00
Comments on this criterion: No clear and decisive final recommendation is evident in the work submitted. The recommendation should clearly meet the needs of the customer.