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We can find l by the Pythagorean theorem:

L2 = r2 + h2

As r=12m and h=9m then l2 = 144+81 = 225 = 152

So l = 15.

Then S = π r(r+l)=1017.87 or 324π

We can find h from the Pythagorean theorem:

L2 – r2 = h2

h2 = 152 – 122 = 81 = 92

So h=9

Then the volume equals 432 π or 1357.16

So S=36π. Then 36 π = 4r2π; So r2 = 9 and r = 3;

Diameter: d=2r = 6

The volume is V=4 π r3/3 = 36 π

We can find h by the Pythagorean theorem:

h2 + d2 = l2

so h2 = l2 – d2 = 302 – 182 = 576 = 242

so h = 24.

Then S = 2 πrh = 216π or 678.58

As the circumference is 14 π = 2 πr, r=7;

The volume can be found by the formula: V = πr2h = 490 π or 1539.38

The lateral surface can be found by the formula: 4ab = 4*4*8= 128 in2

The volume can be found: V = abc = 8*42 = 128 in3

The surface area can be found as S=2Stri + 3Sab = m2

The surface area can be found as S = 6Sab + 2S6 = 6*12*8+6*82/(4tg[360/12]) = 742.3 cm2

The height of the pyramid can be found from the Pythagorean theorem:

L2 – r2 = h2

82 – 62 = h2 = 64-36 = (2)2

So h = 2

The volume can be found as V = Sh/3 = 144*2/3 = 96

The lateral area can be found as 4*12*8/2 = 192

The total surface is base surface + lateral surface = 192 + 122 = 336

The surface area can be found by the formula: S = 3Stri + Sbase = 60 + 4 = 4 (15+)

The volume can be found by the formula: V = ha2/4 = 36/ = 12